c^2+15c+42=c-7

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Solution for c^2+15c+42=c-7 equation: 



c^2+15c+42=c-7

We move all terms to the left:

c^2+15c+42-(c-7)=0

We get rid of parentheses

c^2+15c-c+7+42=0

We add all the numbers together, and all the variables

c^2+14c+49=0

a = 1; b = 14; c = +49;
Δ = b2-4ac
Δ = 142-4·1·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{-14}{2}=-7$

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